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Showing posts from March, 2025

What Makes a Great Flutter App?

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A great Flutter app isn’t just about writing functional code—it’s about ensuring efficiency, scalability, and an outstanding user experience . Let's break down each key point in detail. 1️⃣ Performance Optimization – Avoid Unnecessary Widget Rebuilds Problem: Flutter’s UI is rebuilt whenever setState() is called, but inefficient usage can lead to unnecessary widget rebuilds , causing performance issues. Solution: ✅ Use const constructors for widgets that don’t change. ✅ Use keys to optimize how widgets are updated. ✅ Wrap only the changing part of a widget inside setState() . Example: class CounterScreen extends StatefulWidget { @override _CounterScreenState createState() => _CounterScreenState(); } class _CounterScreenState extends State<CounterScreen> { int _counter = 0; @override Widget build(BuildContext context) { print("Entire screen rebuilt!"); // Bad practice return Scaffold( appBar: AppBar(title: Text("Counte...

What is LEGO, and How Does It Relate to OOP?

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LEGO is a famous toy system where you build things using small, reusable building blocks . Just like you can combine different LEGO pieces to make a car, house, or spaceship, in OOP , you combine objects (small reusable code blocks) to build apps. How LEGO Relates to OOP Concepts 1️⃣ Encapsulation → Hiding Details In LEGO, some pieces have internal mechanisms (like gears inside a LEGO car), but you only interact with the outside (wheels, doors, etc.). In OOP , objects hide internal logic and only expose necessary functionality . Example: class Car { // Private property (hidden from the outside) int _enginePower = 100; // Public method (exposed to users) void drive() { print("Car is driving with $_enginePower horsepower."); } } void main() { Car myCar = Car(); myCar.drive(); // ✅ Allowed // myCar._enginePower = 200; ❌ Not allowed (encapsulated) } 2️⃣ Abstraction → Hiding Complexity When you build a LEGO car , you don’t worry about how...

πŸ” Deep Dive: How Flutter Renders Widgets Efficiently

Flutter is known for its smooth UI and high-performance rendering , but how does it achieve this? Let’s break it down. 1️⃣ The Three-Layer Rendering Pipeline Flutter’s rendering process is divided into three key trees , each serving a unique role: 1. Widget Tree – The UI Blueprint Defines what to build, like buttons, text, and layouts. Created when you write code in Dart using StatelessWidget or StatefulWidget . Example: class MyWidget extends StatelessWidget { @override Widget build(BuildContext context) { return Center(child: Text("Hello, Flutter!")); } } Limitation: Widgets are immutable; when something changes, Flutter replaces widgets instead of modifying them. 2. Element Tree – Manages Widget Lifecycle Tracks live instances of widgets and their states. Ensures widgets are only recreated when necessary . If a widget doesn’t change, Flutter reuses the existing element instead of replacing it. Example: If you navigate from Screen A ...

Core Concept: The Hidden Cost of setState() in Flutter

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  Many beginners in Flutter use setState() liberally, assuming it's the standard way to update UI. But without understanding its true cost, this can lead to performance issues. What Really Happens Under the Hood? Whenever you call setState(): πŸ”Ή The framework marks the widget as "dirty", meaning it needs to be rebuilt. πŸ”Ή The entire widget subtree below the updated widget may rebuild—even if only a small part actually changed. πŸ”Ή This unnecessary rebuilding can cause performance slowdowns, especially in complex UI structures with heavy animations, lists, or real-time updates. How to Use setState() Efficiently? ✅ Minimize the rebuild scope – Wrap only the widgets that need updating instead of affecting the entire tree. ✅ Use keys wisely – Assign ValueKey, ObjectKey, or GlobalKey to widgets to optimize how Flutter updates them. ✅ Consider state management solutions – For complex or shared state, setState() isn't always the best approach. Use: GetX – Lightweight and effi...